k dgw

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9 years, 11 months ago.

Is UART TX/RX pin map image of FRDM-K64F wrong?

The pin map image of FRDM-K64F shows that RX=PTC17, TX=PTC16. But, the User's guide http://cache.freescale.com/files/microcontrollers/doc/ref_manual/K64P144M120SF5RM.pdf shows that PTB16 UART1_RX and PTB17 UART1_TX.

I tested serial communication. Results are the following: NG: Serial test(PTC16,PTC17) OK: Serial test(PTC17,PTC16)

Is that correct?

Question relating to:

Last updated: 27 Aug 2020
The Freedom-K64F is an ultra-low-cost development platform for Kinetis K64, K63, and K24 MCUs.

This has been corrected. Thanks for pointing it out.

posted by Sam Grove 19 May 2014

1 Answer

Martin Kojtal
9 years, 11 months ago.

Hello,

it does not say that USBRX/TX (default serial pins) are PTC pins, at least the first picture on the K64F page. There is UART3 on the picture.

Regards,
0xc0170

Accepted Answer

Thank you for reply.

I am not saying about USBRX/TX.

According to the datasheet http://cache.freescale.com/files/microcontrollers/doc/data_sheet/K64P144M120SF5.pdf PTB16 is UART0_RX, PTB17 is UART0_TX PTC16 is UART3_RX, PTC17 is UART3_TX

The pin map picture says PTC16 is UART3_TX, PTB17 is UART3_RX.

Which one is correct?

Regards

posted by k dgw 16 May 2014

aRe you referring to this picture ? http://mbed.org/media/uploads/sam_grove/k64f_arduino.jpg ? I see UART3 connected to PTC pins (that's correct).

posted by Martin Kojtal 16 May 2014

Sorry, I miss-spelled. I'm confusing

(PTC16, PTC17) = (UART3_TX, UART3_RX)

or

(PTC16, PTC17) = (UART3_RX, UART3_TX)

posted by k dgw 16 May 2014

I see your point now :-) we will fix that picture, thanks ;)

posted by Martin Kojtal 16 May 2014